How to use Reduce in JavaScript
reduce
is an array method that helps you convert an array into a single value. It looks like this:
const callback = (accumulator, currentValue, index) => {
// return something here
}
const result = array.reduce(callback, initialValue)
- initialValue is the value you want to start with.
- accumulator is the value returned from the previous iteration. It will be
initialValue
for the first iteration. - currentValue is array item in the current iteration.
Let’s go through some examples.
Summing numbers
Let’s say you have a list of numbers. You want to find the total sum of these numbers.
const numbers = [1, 2, 3, 4, 5]
Here’s the code to sum the numbers.
const total = numbers.reduce((acc, num) => acc + num, 0)
console.log(total) // 15
Let’s go through what happens, step by step.
First, you pass an initialValue
to reduce
. This initialValue
should be 0 because:
- We want
accumulator
to be a number. - We don’t want the
initialValue
to affect the sum.
Initial value set to 0
accumulator
will be initialValue
in the first iteration. currentValue
will be the first array item.
accumulator assigns as 0
currentValue is the first item in the array
You need to return a value in the callback. This value will be used as the next accumulator
. Since we want to sum numbers, we return the sum of accumulator
and currentValue
.
The next return value is calculated
accumulator
takes on the returned value in the second iteration. currentValue
will be the second array item.
The previous return value is used as the next accumulator
currentValue becomes the second item in the array
We return the sum of the two values we have, accumulator
and currentValue
. This process goes on until reduce
loops through the entire array. The final value will be returned to the function call.
The return value is calculated and the process repeats
Reducing an array into an object
We’ll create the reduce
method together for this example.
Let’s say we have an array of fruits. We want to know the number of each type of fruit.
const fruits = ['apple', 'apple', 'banana', 'banana', 'orange', 'pear', 'apple']
// What you want
// {
// apple: 3,
// banana: 2,
// orange: 1,
// pear: 1
// }
First, we should pass an empty object as the initialValue
because we want to create an object.
const tally = fruits.reduce((accumulator, fruit) => {
// Do something
}, {})
In the first iteration, accumulator
will be {}
. fruit
will be apple
.
In this first iteration, we know the accumulator doesn’t have the fruit yet. ({}
doesn’t contain apple
). Here, we want to add apple
to accumulator
. While adding apple
to accumulator
, we set the number of apples to 1.
const tally = fruits.reduce((accumulator, fruit) => {
return accumulator[fruit] = 1
}, {})
In the second iteration, accumulator
takes on the previously returned value. fruit
is another apple:
accumulator
:{ apple: 1 }
fruit
:apple
Here, we want to increase the number of apples in the accumulator
. To do so, we need to check if the apple
property exists in accumulator
. If it does, we increase its value by 1.
const tally = fruits.reduce((accumulator, fruit) => {
if (accumulator[fruit]) {
accumulator[fruit] = accumulator[fruit] + 1
} else {
accumulator[fruit] = 1
}
return accumulator
}, {})
That’s it! The process repeats for other fruits. If you log tally
, you’ll see the object we wanted.
{
apple: 3,
banana: 2,
orange: 1,
pear: 1
}
Let’s clean up the reduce function next. We can do so with ternary operators.
const tally = fruits.reduce((accumulator, fruit) => {
const fruitCount = accumulator[fruit]
fruitCount
? accumulator[fruit] = fruitCount + 1
: accumulator[fruit] = 1
return accumulator
}, {})
Flattening an array
Let’s say we have an array that contains arrays. We want to convert this array of arrays into a single array that contains all values. This process is called flattening.
const array = [
[1, 2, 3, 4, 5],
[6, 7, 8, 9, 10]
]
// What we want:
// [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
To flatten the array, we need to start the reduce
with an array. This is because we want the output to be an array.
const flattened = array.reduce((accumulator, item) => {
// Do something
}, [])
In the first iteration, accumulator
will be an empty array. item
will be an array that contains five items.
accumulator
:[]
item
:[1, 2, 3, 4, 5]
We want to merge item
into accumulator
. We can use concat
to do so.
const a1 = []
const a2 = [1, 2, 3, 4, 5]
const merged = a1.concat(a2)
console.log(merged) // [1, 2, 3, 4, 5]
This method works even if accumulator contains values.
const a1 = [1, 2, 3]
const a2 = [4, 5]
const merged = a1.concat(a2)
console.log(merged) // [1, 2, 3, 4, 5]
The reduce
code looks like this:
const flattened = array.reduce((accumulator, item) => {
return accumulator.concat(item)
}, [])
If you want to make it shorter, you can use the array spread operator.
const flattened = array.reduce(
(accumulator, item) => [...accumulator, ...item], []
)
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