Two ways to solve Binary Search Algorithm :

Test array

arr = [ 2, 3, 4, 10, 40 ]
x = 10

if x in arr:
for y in range(len(arr)):
if arr[y] == x:
print("Element is present at index ", y)
else:
print(“Element is not present in the array”)

if x in arr:
for index, item in enumerate(arr):
if item == x:
print("Element is present at index ", index)
else:
print(“Element is not present in the array”)

HANGMAN :

Hangman game

def gameplay():
secret_word = input(“Player one, please enter your secret word : “)
for w in range(50):
print(w*””)
secret = “_” * len(secret_word)
secret = list(secret)
print("Player 2 must guess Player’s one’s guess ")
current_progress = “”
failed_guesses = 0
while current_progress != secret_word:
guess = input("Player 2, please guess a letter : ")
if guess in secret_word:
for i in range(len(secret_word)):
if secret_word[i] == guess:
secret[i] = guess
final = “”
for x in secret:
final += x

        print("Current progress : ", final)
        if secret_word == final :
            print("You won!!!")    
            break
    
    else:
        failed_guesses += 1
        print("You guess is incorrect, please try again!")
        print("Hangman status : ", end="")
        
        if failed_guesses == 1:
            print("O")
        elif failed_guesses == 2:
            print("0-")
        elif failed_guesses == 3:
            print("0_0")
        elif failed_guesses == 4:
            print("0-<")
        elif failed_guesses == 5:
            print("0+<")
        elif failed_guesses == 6:
            print("You died!!")
            
        print("Number of chances left : ", 6-failed_guesses)
        for p in range(2):
            print(p*"")
        if failed_guesses == 6:
            print("You lost!!")
            break
        

print("Thank you for playing hangman!")

gameplay()

I made an enhanced version of the Number Guessing Game with 2 play modes and a way better UI. Check it out: https://github.com/ShakeelAhmed123/Simple-Python-Number-Guessing-Game

HELLO WORLD !! PLEASE CORRECT ME, I SOLVED EM ALL:

###THE BINARY SEARCH ALGO

import random
def div(l):
if len(l) %2 == 0:
B =[]
for k in range(0,int(len(l)/2)):
B.append(l[k])
S = []
for i in range(int(len(l)/2)+1,len(l)):
S.append(l[i])

    return [S ,B]
if len(l)%2 ==1:
    H1 = []
    for k in range(0,int(len(l)/2)+1):
        H1.append(l[k])
    H2 = []
    for i in range(int(len(l)/2)+1,len(l)):
        H2.append(l[i])
    return [H1,H2]

def inhalf(n, L):
if n in L[0]:
return L[0]
if n in L[1]:
return L[1]
def cent(L):
return L[int(len(L)/2)+1]

R = [k for k in range(0,101)]
R = random.sample(R,101)
print®

u = int(input(“HEY! guess a number between 0 and 100”))
print(“I generated a random list of numbers between 0 and 100”)
if u == cent® :
print(“U WON , IT WAS IN THE MIDDLE OF MY RLIST {}”.format(u))
else :

while u in inhalf(u,div(R)) and len(R)> 2:
    R = inhalf(u,div(R))
    print("we found it in here")
    print(R)

cos vs sin (I am not sure i understood well what is asked

import numpy as np
import matplotlib.pyplot as plt

X = np.linspace(-2np.pi,2np.pi,100)
Y = np.cos(X)
Z = np.sin(X)

plt.plot(X,Y)

plt.plot(X,Z)
plt.show()

###guess a number

import random
a = random.randint(0,20)
b = int(input(“guess a number between zero and twenty”))
if b==a :
print(“good guess”)
while a != b :
if b<a :
print(“too small”)
b = int(input(“guess again”))

if b>a :
    print("too high")
    b = int(input("guess again"))
if b==a :
    print("good guess")

hangman

import random

while input(“wanna play ?”) == “yes”:
#convert the word to a list of letters
def Convert(string):
list1=[]
list1[:0]=string

    return list1
#choose the random word
with open('sowpods.txt') as f:
    words = list(f)
    word = random.choice(words).strip()
L = Convert(word)
U = [0 for x in range(1,len(L)+1)]
print(L)
print(U)
l = len(L)
#the interaction u/c
print("welcome to hungman, the word i have in mind counts :{} letters".format(l))
print("u have the right to make 6 wrong guesses")
cp = 0

while cp < 7 and U != L:
    u = input("enter a letter")
    if u not in L:
        cp +=1
        print("false")
    if cp == 7: 
        print("GAME OVER LOOOOSER, U are hunged motherfucker")
    else:
        k = 0
        p = 0
        while k != l:
            for i in range (0,l):
                if L[i] != u :
                    k+=1
                else : 
                    print("the letter u gave is in the : {}position" .format(k+1))  
                    U[k] = u
                    print(U)
                    k += 1
                
        if L == U:
            print("GOOD JOB DUM DUM !! the word was : "+ str(word))

password generator

import string
import numpy as np
import random
Le = string.ascii_letters
Nu = [“0”,“1”,“2”,“3”,“4”,“5”,“6”,“7”,“8”,“9”]

Python code to convert string to list character-wise

def Convert(string):
list1=[]
list1[:0]=string
return list1

le = Convert(Le)
nu = Convert(Nu)

Python program to convert a list to string

Function to convert

def listToString(s):

# initialize an empty string 
str1 = ""  

# traverse in the string   
for ele in s:  
    str1 += ele   

# return string   
return str1 

def password(L,N):
l = []
n = []
if N + L <6:
print(“error, the password must contain at least 6 carac”)
else :

    while len(l) != L:
        l.append(random.choice(le))
    print(l)
    
    while len(n) != N:
        n.append(random.choice(nu))
    print(n)

    f = random.sample(n+l,len(n+l))
    return str(listToString(f))

rock,scissor,paper

import random
L = [“rock”, “scissor”,“paper”]
u = str(input(“let’s play ! Wanna start ?”))
while u != “no”:

value = str(input("rock,scissor,paper"))
c = random.choice(L)
print(c)
if c == value:
    print("we're even")
if c == L[0] and value == L[1] or c == L[1] and  value == L[2] or c == L[2] and value == L[0] :
    print("I won")
if c == L[0] and value == L[2] or c == L[2] and value == L[1] or value == L[0] and c == L[1]:
    print("u won")